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8w^2-83w+210=0
a = 8; b = -83; c = +210;
Δ = b2-4ac
Δ = -832-4·8·210
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-83)-13}{2*8}=\frac{70}{16} =4+3/8 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-83)+13}{2*8}=\frac{96}{16} =6 $
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